In a Punnett square, if both parents are heterozygous for a trait with allele T dominant and t recessive, what is the probability of a homozygous recessive offspring (tt)?

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Multiple Choice

In a Punnett square, if both parents are heterozygous for a trait with allele T dominant and t recessive, what is the probability of a homozygous recessive offspring (tt)?

Explanation:
When both parents have Tt, each parent can pass on either T or t. The four possible offspring genotypes are TT, Tt, tT, and tt, all with equal likelihood. The homozygous recessive genotype is tt, so only one of the four outcomes is tt. That makes the probability 1/4, or 25 percent. (Phenotypically, tt would show the recessive trait, while the other three combinations show the dominant trait.)

When both parents have Tt, each parent can pass on either T or t. The four possible offspring genotypes are TT, Tt, tT, and tt, all with equal likelihood. The homozygous recessive genotype is tt, so only one of the four outcomes is tt. That makes the probability 1/4, or 25 percent. (Phenotypically, tt would show the recessive trait, while the other three combinations show the dominant trait.)

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